c++ - doubts regarding usage of :: (scope_resolution_operator) -
when studying book on c++, came across this. if declare class, class student {public: void func(int v1,int v2) { //some code } //some members. }; and use function same name out of class (non-member function) like, void func(int x,inty) and if wish call non-member function in member function of above declared class, syntax be, //inside member function... ::func(x,y); } correct me if wrong.otherwise, assuming wrote using namespace std; in beginning of program, below code equivalent previous one? //inside member function std::func(x,y); } and, answer change if use different namespace other std?? ie, provided use, using namespace abc are following declarations abc::func(x,y) and, ::func(x,y) absolutely equivalent under conditions or change under specific conditions?? thank you. in beginning of program, below code equivalent previous one? //inside member function std::func(x,y); no isn't. because preform qualified name lookup...
