arguments - Python - check if arg from arparse was chosen -
i check if argument argsparse chosen, if not choose random value variable.
here example:
parser.add_argument('--tempo', default=120, type=int, help='tempo of track')
and 1 way example:
args = parser.parse_args() if args.tempo==120: #my default int tempo=random.randint(60,350)
but way when user call program example: main.py --tempo 120
, choose random value. how can check if argument chosen or not?
the problem in test. if user chose 120 give random number. think best remove default , check if empty.
parser.add_argument('--tempo', default=none, type=int, help='tempo of track') args = parser.parse_args() if args.tempo==none: #my default int args.tempo=randint(60,350)
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