XSLT with XML source that has a default namespace set to xmlns -

i have xml document default namespace indicated @ root. this:

<myroot xmlns="http://www.mysite.com">    <mychild1>        <mydata>1234</mydata>     </mychild1>  </myroot> 

the xslt parse xml not work expected because of default namespace, i.e. when remove namespace, works expected.

here xslt:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/xsl/transform"             xmlns:xs="http://www.w3.org/2001/xmlschema">  <xsl:template match="/" >   <soap:envelope xsl:version="1.0" xmlns:xsi="http://www.w3.org/2001/xmlschema-instance"  xmlns:xsd="http://www.w3.org/2001/xmlschema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">    <soap:body>      <newroot xmlns="http://wherever.com">        <newchild>          <childid>abcd</childid>          <childdata>             <xsl:value-of select="/myroot/mychild1/mydata"/>          </childdata>        </newchild>      </newroot>    </soap:body>   </soap:envelope>  </xsl:template> </xsl:stylesheet> 

what needs done xslt document translation works properly? needs done in xslt document?

you need declare namespace in xslt, , use in xpath expressions. e.g.:

<xsl:stylesheet ... xmlns:my="http://www.mysite.com">     <xsl:template match="/my:myroot"> ... </xsl:template>  </xsl:stylesheet> 

note must provide prefix if want refer elements namespace in xpath. while can xmlns="..." without prefix, , work literal result elements, won't work xpath - in xpath, unprefixed name considered in namespace blank uri, regardless of xmlns="..." in scope.