python - Replace Numpy NaN with string in list with strings -

i have list containing string elements, , several nan numpy floats. e.g.

l=['foo', 'bar', 'baz', 'nan'] 

how replace float nan string missing?

most answers found regard issue in pandas dataframe.

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try 1:

for x in l:     x=x.replace('nan', 'missing') 

gives attributeerror: 'float' object has no attribute 'replace'

try 2:

for x in l:    if str(x)=='nan':        x=str(x) 

command executes, nothing changes.

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advised comments:

1. ['missing' if x 'nan' else x x in l]
2. ['missing' if x np.isnan else x x in l]
3. ['missing' if x np.nan else x x in l]

commands execute, nothing changes.

i think have bad format nan's (notice nan outputed nan , not 'nan'). answers comment should work:

>>> import numpy np >>> l=['foo', 'bar', 'baz', np.nan] >>> print l ['foo', 'bar', 'baz', nan] >>> l_new=['missing' if x np.nan else x x in l] >>> print l_new ['foo', 'bar', 'baz', 'missing'] 

for current problem maybe make following solution:

my_nan=l['some_index_with_nan'] l_new=['missing' if x my_nan else x x in l]